RemoteApp with dynamic command-line arguments

hi.

 

i want launch remoteapp dynamic argument this:

"myprogram.rdp /param1 /param2"

it means, want give parameters program launched in server.

can it? :)

 

thanks.

hello,

i think making bit difficult :-). correct me if wrong......... trying create rdp file launch application default. application should start changing parameters??

in case setup file share users of application have access , create rdp file(s) there , set approprate permissions on files. in way there central location changing rdp files.

regards robert

Windows Server  >  Remote Desktop Services (Terminal Services)